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Groovy Sort List

Groovy Sort List

I am posting a simple example on how to sort a list in groovy because the examples google knows about arent what I was looking for. With some deep digging I was able to find a clue that eventually solved my problem.

Its real easy to sort a list of numbers

assert [1,2,3,4] == [3,4,2,1].sort()

Or even strings

assert [Chad,James,Travis] == [James,Travis,Chad].sort()

But this was my example

class Person {
 String id
 String name
}

def list = [new Person(id: 1, name: James),new Person(id: 2, name: Travis), new Person(id: 3, name: Chad)]

list.sort() returns James, Travis, Chad

The solution is ridiculously simple (not that I thought the previous sort would work; I have to be realistic; groovy cant do everything for me).

list.sort{it.name} will produce an order of Chad, James, Travis.

In the previous example note the use of the sort closure sort {} verses the sort() method.

Now I am not sure, off the top of my head and without a Groovy book handy, the simplest way to sort case insensitive.

assert [a1,A1] == [A1,a1].sort{fancy closure}

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